Wheatstone bridge schematic
R1, R3, R4
adjusted for im = 0
:R2 = R1*R4/R3For unbalanced bridges, given
v, im
and fixed resistors,i1, i2, i3, i4, R2
values[1], [2], [3], [4], [5]
by Kirchhoff's circuit laws:i1 = im + i2 [1] im = i4 - i3 [2] im*Rm = i3*R3 - i1*R1 [3] im*Rm = i2*R2 - i4*R4 [4]Instead of ideal EMF source
v
,Vf
with source impedance Rs ~ Rm
:
Vf + (i1 + i3)*Rs + i1*R1 + i2*R2 = 0 [5]
im
vs R2
derivationR1 = R3 = R4 = Rm
, then:
im = i3 - i1 [6] // from [3] 2*im = i3 - i2 [7] // [6], [1] 2*im = i4 - i1 [8] // [6], [2] i3 = i2 + 2*im [9] // [7] i4 = 2*im + i1 = 3*im + i2 [10] // [8], [1]Eliminate
i1, i3
using [1], [9]
:
Vf + (im + i2 + i2 + 2*im)*Rs + (im + i2)*R1 + i2*R2 = 0 // [5] Vf + 3*im*Rm + 2*i2*Rm + im*Rm + i2*Rm + i2*R2 = 0 // Rs ~ Rm = R1 i2 = - (Vf + im*3*Rm + im*Rm)/(3*Rm + Rm) = -im - Vf/(4*Rm) [11] i2 = im*Rm/R2 + i4*Rm/R2 // [4] = im*Rm/R2 + (3*im + i2)*Rm/R2 // [10] = 4*im*Rm/R2 + i2*Rm/R2Multiply by R2/Rm and rearrange:
4*im = (-1 + R2/Rm)*i2 = (-1 + R2/Rm)*(-im - Vf/(4*Rm)) // [11] = (1 - R2/Rm)*(im + Vf/(4*im)) = im + Vf/(4*im) - im*R2/Rm -Vf*R2/(4*im*Rm) 3*im = Vf/(4*im) - im*R2/Rm -Vf*R2/(4*im*Rm)Multiple by
4*im*Rm
and rearrange: 12*Rm*im*im = Vf*Rm - 4*R2*im*im - Vf*R2 im*im*(12*Rm + 4*R2) = Vf*(Rm - R2) im = sqrt(Vf*(Rm - R2)/(12*Rm + 4*R2))
R2
range provokes less than 10% response change.
set xrange [0:1000] set yrange [-4:2.5] set xtics 50 set ytics 0.5 set grid xtics ytics set ylabel "arbitrarily scaled 50 Ohm response" set xlabel "unknown R2 in Ohms" set title "unbalanced 50 Ohm bridge" p (x<50)?8*sqrt((50-x)/(600 + 4*x)) : -8*sqrt((x-50)/(600 + 4*x)) title "meter current i_m"